Lamp A, because it has lowest power rating. And since, voltage is constant in all the 3 cases, therefore, Resistance is inversely proportional to power.

Answer will be lamp A, since, P = V^2/ R and therefore, resistance is inversely proportional to power. We find here that the V is comstant and the only varying quantity is P . Therefore, R will be least in lamp A (R1 = 220/0.18 , R2 = 220/ 0.28, R3= 220/0.45)

Answer will be lamp A, since, P = V^2/ R and therefore, resistance is inversely proportional to power. We find here that the V is comstant and the only varying quantity is P . Therefore, R will be least in lamp A (R1 = 220/0.18 , R2 = 220/ 0.28, R3= 220/0.45)

lamp A

ReplyDeleteLamp A, because it has lowest power rating. And since, voltage is constant in all the 3 cases, therefore, Resistance is inversely proportional to power.

ReplyDelete(A) is the answer as by using formula R=(v^2)/p we can get answer easily

ReplyDeleteAnswer will be lamp A, since, P = V^2/ R and therefore, resistance is inversely proportional to power. We find here that the V is comstant and the only varying quantity is P . Therefore, R will be least in lamp A

ReplyDelete(R1 = 220/0.18 , R2 = 220/ 0.28, R3= 220/0.45)

Answer will be lamp A, since, P = V^2/ R and therefore, resistance is inversely proportional to power. We find here that the V is comstant and the only varying quantity is P . Therefore, R will be least in lamp A

ReplyDelete(R1 = 220/0.18 , R2 = 220/ 0.28, R3= 220/0.45)